Lesson 4: Revision and Practice

📘 Introduction

This revision lesson brings together all you’ve learned in this module: plotting points, recognizing solids, calculating perimeters, areas, and solving real-world geometry problems.

Test your knowledge, build confidence, and sharpen your exam readiness through these carefully designed exercises!

🧠 Section A: Coordinates and the Number Plane

1. Plot the following points and name the shape they form: A(2, 2), B(2, 5), C(5, 5), D(5, 2).
2. Which quadrants do the following points lie in?
   a. P(−4, 3) b. Q(−2, −5) c. R(3, −1) d. S(1, 4)
3. Draw and connect the points (−1, −1), (−1, 2), (2, 2), and (2, −1). Shade the figure and state the name of the shape.

📦 Section B: Solids – Recognition and Properties

4. Match the solids to their properties:
   a. Cube      i. 2 flat faces, 1 curved face, 1 vertex
   b. Cylinder    ii. 6 equal square faces
   c. Cone      iii. 2 circular faces, 1 curved side
5. Complete the table below:

📐 Section C: Perimeter and Area

6. A triangular farm has a base of 12 m and a height of 8 m. Find its area.
7. A rectangular room is 9 m long and 6 m wide. What is its perimeter and area?
8. A circular mat has a radius of 7 cm. Find its area and circumference. Use π = 3.14.
9. A compound shape is made of a rectangle (10 m by 4 m) and a semicircle on one short side (radius 2 m). Find the total area.

📝 Suggested Answers

• Q1: A square (all sides equal and right angles)
• Q2: P – II, Q – III, R – IV, S – I
• Q3: Rectangle
• Q4: a-ii, b-iii, c-i
• Q5:
  Cube – 6 faces, 12 edges, 8 vertices
  Sphere – 1 face, 0 edges, 0 vertices
  Cuboid – 6 faces, 12 edges, 8 vertices
• Q6: Area =
• Q7: Perimeter = 2(9 + 6) = 30 m, Area = 54 m²
• Q8: Area = , Circumference =
• Q9: Rectangle = 40 m²; Semicircle = (1/2 × π × 4) ≈ 12.56 m²; Total ≈ 52.56 m²

🔁 Recap

• You can identify and describe solids by their faces, edges, and vertices
• Coordinate geometry helps you plot points and create shapes
• Perimeter is the total distance around a shape; area is the space inside
• Compound shapes can be split into simple parts for easy calculations

🪞Reflection Prompt

Which types of problems in this module did you find easiest? Which ones challenged you the most? What will you review again to strengthen your understanding?